document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=857815>Question 857815</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 112-2x is 68 then what is x? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #516860 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=516860\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 112 - 2x = 68<BR>\n" );
document.write( "Add 2x to each side<BR>\n" );
document.write( "112 = 2X + 68<BR>\n" );
document.write( "Subtract 68 from each side<BR>\n" );
document.write( "112-68 = 2x<BR>\n" );
document.write( "44 = 2x<BR>\n" );
document.write( "Divide each side by 2<BR>\n" );
document.write( "22 = x<BR>\n" );
document.write( ".<BR>\n" );
document.write( "It's the negative 2x that confuses people.  Remember that we can anything to both sides as long as we do it equally. </SPAN>\n" );
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