document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=72306>Question 72306</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sirs, I am seeking help with my sons Algebra as I am really struggling to comprehend the basics.\r<BR>\n" );
document.write( "\n" );
document.write( "(Multiply by the denominator to eliminate the denominator, but remember to do so on both sides. Then eliminate the number in front of the letter by division.)\r<BR>\n" );
document.write( "\n" );
document.write( "2a=-2<BR>\n" );
document.write( "3\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The 1st numbers are fractions ie 2a over 3.<BR>\n" );
document.write( "Very grateful for any help.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #51686 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=51686\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2a/3=-2 now we need to cross multiply thus: 2a/3=-2/1 (2a*1)=(-2*3)<BR>\n" );
document.write( "2a=-2*3<BR>\n" );
document.write( "2a=-6<BR>\n" );
document.write( "a=-6/2<BR>\n" );
document.write( "a=-3 answer. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );