document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=857513>Question 857513</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An arrow shot into the air is 160x-16x^2 feet above the ground \"x\" seconds after it is released. During what period of time is the arrow above 384 feet? Please include a step-by-step explanation of how you got the answer. Thank You. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #516855 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=516855\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 160x-16x^2 =384<BR>\n" );
document.write( "put in order<BR>\n" );
document.write( "-16x^2 +160x-384=0<BR>\n" );
document.write( "multiply by -1<BR>\n" );
document.write( "16x^2-160x+384=0<BR>\n" );
document.write( "divide by 16<BR>\n" );
document.write( "x^2-10x+24=0<BR>\n" );
document.write( "factor<BR>\n" );
document.write( "(x-4)(x-6)=<BR>\n" );
document.write( "x=4 and x=6<BR>\n" );
document.write( "on its way up and on its way down  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );