document.write( "Question 857779: hello. I need help solving this problem please. \r
\n" ); document.write( "\n" ); document.write( "suare root of 3x+1 +2 = square root of 5x+9 \n" ); document.write( "

Algebra.Com's Answer #516826 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"sqrt%283x%2B1%29%2B2=sqrt%285x%2B9%29\"$
\n" ); document.write( "Square both sides.
\n" ); document.write( " $\"%28sqrt%283x%2B1%29%2B2%29%28sqrt%283x%2B1%29%2B2%29=5x%2B9\"$
\n" ); document.write( " $\"%283x%2B1%29%2B4sqrt%283x%2B1%29%2B4=5x%2B9\"$
\n" ); document.write( " $\"4sqrt%283x%2B1%29=5x%2B9-3x-1-4\"$
\n" ); document.write( " $\"4sqrt%283x%2B1%29=2x%2B4\"$
\n" ); document.write( " $\"2sqrt%283x%2B1%29=x%2B2\"$
\n" ); document.write( "Square both sides again.
\n" ); document.write( " $\"4%283x%2B1%29=x%5E2%2B4x%2B4\"$
\n" ); document.write( " $\"12x%2B4=x%5E2%2B4x%2B4\"$
\n" ); document.write( " $\"x%5E2-8x=0\"$
\n" ); document.write( " $\"x%28x-8%29=0\"$
\n" ); document.write( "Two possible solutions:
\n" ); document.write( " $\"highlight%28x=0%29\"$
\n" ); document.write( "and
\n" ); document.write( " $\"x-8=0\"$
\n" ); document.write( " $\"highlight%28x=8%29\"$
\n" ); document.write( "Make sure you go back and verify that these are actual solutions, a critical step for these type of problems. \n" ); document.write( "

\n" );