document.write( "Question 857703: Find the centroid of the area under
\n" ); document.write( "y = 1 + x + {x}^{2}
\n" ); document.write( " from x = 0 to x = 2
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Algebra.Com's Answer #516824 by rothauserc(4718)\"\" \"About 
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first integrate and evaluate y = 1 + x + {x}^2
\n" ); document.write( "x+C +x^2/2 +x^3/3
\n" ); document.write( "Area under curve evaluated for x =0 to 2 is
\n" ); document.write( "2+2+8/3 = 6 2/3
\n" ); document.write( "the centroid of the area is total moments / area
\n" ); document.write( "total moments = integral from x = 0 to 2 of x*f(x)dx
\n" ); document.write( "x*f(x) = x + x^2 + x^3
\n" ); document.write( "now integrate x + x^2 + x^3
\n" ); document.write( "x^2/2 + x^3/3 + x^4/4
\n" ); document.write( "evaluate for x = 0 to 2
\n" ); document.write( "2 + 8/3 + 4 = 8 2/3
\n" ); document.write( "now calculate (8 2/3) / (6 2/3) = (26/3) / (20/3) = (26 * 3) / (20 * 3) = 1.3
\n" ); document.write( "centroid of the area is 1.3
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