document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=857283>Question 857283</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given numbers a,b,c find x: a+x, b+x, c+x are<BR>\n" );
document.write( "consecutive in a geometric sequence. What is x? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #516805 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=516805\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For a+x, b+x, c+x to form a geometric sequence, we must have <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\large (b+x)^2 = (a+x)(c+x) \Rightarrow x^2 + 2bx + b^2 = x^2 + (a+c)x + ac\">. Subtract x^2 from both sides and you will obtain <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\large b^2 - ac = (a+c-2b)x \Rightarrow x = \frac{b^2 - ac}{a+c-2b}\">, provided this number exists. </SPAN>\n" );
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