document.write( "Question 857697: Ten years ago, Bob was three times as old as Anna. Today, he is twice as old as Anna. How old is Bob today? \n" ); document.write( "

Algebra.Com's Answer #516787 by Seutip(231) $\"\"$ $\"About$

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Ten years ago:
\n" ); document.write( "x - Anna's age
\n" ); document.write( "3x - Bob's age\r
\n" ); document.write( "\n" ); document.write( "Present:
\n" ); document.write( "x+10 - Anna's age
\n" ); document.write( "3x+10 - Bob's age\r
\n" ); document.write( "\n" ); document.write( "Therefore:\r
\n" ); document.write( "\n" ); document.write( " $\"3x%2B10+=+2%28x%2B10%29\"$
\n" ); document.write( " $\"3x%2B10+=+2x%2B20%29\"$
\n" ); document.write( " $\"x+=+10%29\"$ \r
\n" ); document.write( "\n" ); document.write( "Therefore their ages now are:
\n" ); document.write( "Bob = 3x+10 = 40 y.o.
\n" ); document.write( "Anna = x+10 = 20 y.o.\r
\n" ); document.write( "\n" ); document.write( "HOPE THAT HELPS!\r
\n" ); document.write( "\n" ); document.write( "@seutip in twitter and insta give me a follow click. \n" ); document.write( "

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