document.write( "Question 857706: Can you help me to solve these two equations by using the substitution method.\r
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document.write( "2x + 4y = -6
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document.write( "x - 3y = 7\r
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document.write( "x = 2y + 2
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document.write( "2x + 3y = 11 \n" );
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Algebra.Com's Answer #516768 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 2 x + 4 y = -6 .............1 \n" ); document.write( "4 y = -6 + -2 x \n" ); document.write( "/ 4 = \n" ); document.write( " y = -1.5 + -0.5 x \n" ); document.write( "1 x + -3 y = 7 .....................2 \n" ); document.write( "Substitute y in (2) \n" ); document.write( "1 x + -3 ( -1.5 + -0.5 x ) = 7 \n" ); document.write( "1 x + 4.5 + 1.5 x = 7 \n" ); document.write( "1 x 1.5 x = 2.5 \n" ); document.write( "2.5 x = 2.5 \n" ); document.write( "/ 2.5 \n" ); document.write( "x= 1 \n" ); document.write( "Plug the value of x in (1) \n" ); document.write( "2 x + 4 y = -6 \n" ); document.write( "2 * 1 + 4 y = -6 \n" ); document.write( "2 + 4 y = -6 \n" ); document.write( "4 y = -8 \n" ); document.write( "/ 4 \n" ); document.write( "y= -2 \r \n" ); document.write( "\n" ); document.write( "x=1,y=-2\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "----------------\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |