document.write( "Question 857683: divide rs 25000 between a,b and c so that a gets 7/8 of b and c gets 2/3 of a and b. \n" ); document.write( "
Algebra.Com's Answer #516759 by dkppathak(439)\"\" \"About 
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divide rs 25000 between a,b and c so that a gets 7/8 of b and c gets 2/3 of a and b.
\n" ); document.write( "Answer
\n" ); document.write( "as per given conditions we will get
\n" ); document.write( "a=7b/8 (1)
\n" ); document.write( "a/b=7/8
\n" ); document.write( "as per other condition
\n" ); document.write( "c=2(a+b)/3 (2)
\n" ); document.write( " a+b+C =25000(3)
\n" ); document.write( "by putting the value of (1) and (2) in (3)
\n" ); document.write( "7b/8+b+2(a+b)/3=25000
\n" ); document.write( "7b/8+b+2(7b/8+b)/3=25000
\n" ); document.write( "(7b+8+b)(1+2/3)=25000
\n" ); document.write( "(7b+8b)/8(5/3)=25000
\n" ); document.write( "(15b/8)x5/3=25000
\n" ); document.write( "75b/24=25000
\n" ); document.write( "b=25000x24/75
\n" ); document.write( "b=8000
\n" ); document.write( "now a=7b/8
\n" ); document.write( "a=7x8000/8=7000
\n" ); document.write( "c=(a+b)x2/3
\n" ); document.write( "c=(7000+8000)x2/3
\n" ); document.write( "c=15000x2/3=10000
\n" ); document.write( "Answer
\n" ); document.write( "a=7000
\n" ); document.write( "b=8000
\n" ); document.write( "c=10000
\n" ); document.write( "verification
\n" ); document.write( "a+b+c=25000
\n" ); document.write( "7000+8000+10000=25000
\n" ); document.write( "verified \r
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