document.write( "Question 857534: On a recent trip, a trucker traveled 225 mi at a constant rate. Because of road conditions, the trucker then reduced the speed by 40 mph. An additional 35 mi was traveled at the reduced rate. The entire trip took 4 h. Find the rate of the trucker for the first 225 mi. \n" ); document.write( "
Algebra.Com's Answer #516735 by lwsshak3(11628)\"\" \"About 
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On a recent trip, a trucker traveled 225 mi at a constant rate. Because of road conditions, the trucker then reduced the speed by 40 mph. An additional 35 mi was traveled at the reduced rate. The entire trip took 4 h. Find the rate of the trucker for the first 225 mi.
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\n" ); document.write( "let x=rate of the trucker for the first 225 mi
\n" ); document.write( "travel time=distance/rate
\n" ); document.write( "..
\n" ); document.write( "\"225%2Fx%2B35%2F40=4\"
\n" ); document.write( "LCD:40x
\n" ); document.write( "40*225+35x=40x*4\r
\n" ); document.write( "\n" ); document.write( "9000+35x=160x
\n" ); document.write( "125x=9000
\n" ); document.write( "x=72
\n" ); document.write( "rate of the trucker for the first 225 mi=72 mph
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