document.write( "Question 857651: At a movie theater a family buys 2 adult tickets and 1 child ticket for a total of $18.00. Another family buys 1 adult ticket and 3 child tickets for a total of $21.50. What is a linear equation that can be used to determine the price of an adult ticket and the price of a child ticket? \n" ); document.write( "
Algebra.Com's Answer #516705 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! 2A + 1C = 18 \n" ); document.write( "1A + 3C = 21.50 \n" ); document.write( "Add them together \n" ); document.write( "3A + 4C = 39.50 \n" ); document.write( ". \n" ); document.write( "Here's my brain's way of going about it. \n" ); document.write( "We know that an adult's ticket ends in .50 (the first equation is even; the second is odd). \n" ); document.write( "We can assume that an adult ticket is priced higher than a child's. With that assumption... \n" ); document.write( "We can tell that an adult ticket is no more than 7.50 and no less than 6.50. \n" ); document.write( "Plug the values in to see: \n" ); document.write( "2(6.50) + C = 18. C would be 5 \n" ); document.write( "2(7.50) + C = 18. C would be 3 \n" ); document.write( "Let's try the 7.50 into the second equation: \n" ); document.write( "7.50 + 9 does not equal 21.50. Oops! \n" ); document.write( "What about the other? \n" ); document.write( "6.50 + 15 does equal 21.50. Success! \n" ); document.write( "The adult ticket is $6.50 and the child's ticket is $5 (must be a matinee!) \n" ); document.write( " |