document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=857589>Question 857589</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangular garden is 10 feet longer than its width. The garden's perimeter is 192 feet. Find the length of the garden. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #516690 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=516690\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter fence around the garden is 192.  That represents 2 pieces of length and 2 pieces of width.<BR>\n" );
document.write( "2L + 2W = 192<BR>\n" );
document.write( "L = W + 10<BR>\n" );
document.write( "Substitute the value of L in the second equation into the first.<BR>\n" );
document.write( "2(W+10) + 2W = 192<BR>\n" );
document.write( "2W + 20 + 2W = 192<BR>\n" );
document.write( "4W + 20 = 192<BR>\n" );
document.write( "4W = 172<BR>\n" );
document.write( "W = 43<BR>\n" );
document.write( "If the width is 43, then the length is 53.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Check by building a fence.<BR>\n" );
document.write( "43+43+53+53=192<BR>\n" );
document.write( "Add<BR>\n" );
document.write( "192 = 192<BR>\n" );
document.write( "Success!<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );