document.write( "Question 857338: a man is five year older than his wife and 7 times as old as his son when the son was born the age of the wife was five all over six hats of husbands age.find their ages?
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Algebra.Com's Answer #516558 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Let their present ages be m, w, s \n" ); document.write( "write an equation for each statement, simplify \n" ); document.write( ": \n" ); document.write( " a man is five year older than his wife \n" ); document.write( "m = w + 5 \n" ); document.write( "and 7 time older than his son \n" ); document.write( "m = 7s \n" ); document.write( "when the son was born, the age of the wife was \n" ); document.write( "subtract the son's age from both \n" ); document.write( "w - s = \n" ); document.write( "replace m with 7s \n" ); document.write( "w - s = \n" ); document.write( "w - s = \n" ); document.write( "Cancel 6 \n" ); document.write( "w - s = 5s \n" ); document.write( "w = 5s + s \n" ); document.write( "w = 6s \n" ); document.write( "In the first equation m = w + 5 \n" ); document.write( "replace m with 7s, replace w with 6s \n" ); document.write( "7s = 6s + 5 \n" ); document.write( "7s - 6s = 5 \n" ); document.write( "s = 5 yrs is the son's age: \n" ); document.write( "I'll let you find the man and the wife's ages\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |