document.write( "Question 857338: a man is five year older than his wife and 7 times as old as his son when the son was born the age of the wife was five all over six hats of husbands age.find their ages?
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Algebra.Com's Answer #516558 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Let their present ages be m, w, s
\n" ); document.write( "write an equation for each statement, simplify
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\n" ); document.write( " a man is five year older than his wife
\n" ); document.write( "m = w + 5
\n" ); document.write( "and 7 time older than his son
\n" ); document.write( "m = 7s
\n" ); document.write( "when the son was born, the age of the wife was \"5%2F6\" that of the husbands age.
\n" ); document.write( "subtract the son's age from both
\n" ); document.write( "w - s = \"5%2F6\"(m - s)
\n" ); document.write( "replace m with 7s
\n" ); document.write( "w - s = \"5%2F6\"(7s-s)
\n" ); document.write( "w - s = \"5%2F6\"(6s)
\n" ); document.write( "Cancel 6
\n" ); document.write( "w - s = 5s
\n" ); document.write( "w = 5s + s
\n" ); document.write( "w = 6s
\n" ); document.write( "In the first equation m = w + 5
\n" ); document.write( "replace m with 7s, replace w with 6s
\n" ); document.write( "7s = 6s + 5
\n" ); document.write( "7s - 6s = 5
\n" ); document.write( "s = 5 yrs is the son's age:
\n" ); document.write( "I'll let you find the man and the wife's ages\r
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