document.write( "Question 857407: Driver 1 moves at 70mph. Driver 2 moves at 97mph
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document.write( "Driver 2 starts 2 minutes after Driver 1\r
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document.write( "How long will it take driver 2 to catch up? \n" );
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Algebra.Com's Answer #516555 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! In two minutes driver 1 goes 2/60*70= 7/3=2 1/3 miles \n" ); document.write( "Driver 2 goes 27 mph faster than driver 1\r \n" ); document.write( "\n" ); document.write( "27*t=7/3*60 \n" ); document.write( "t = 140/27 \n" ); document.write( "t = 5.1852 minutes which is a little more than 5 minutes and 11 second\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |