document.write( "Question 72144This question is from textbook Algebra and Trigonometry: Structure and Method
\n" ); document.write( ": An elevator went from the bottom to the top of a 240 m tower, remained there for 12 s, and returned to the bottom in an elapsed time of 2 min. If the elevator traveled 1 m/s faster on the way down, find its speed going up. \n" ); document.write( "
Algebra.Com's Answer #51654 by josmiceli(19441)\"\" \"About 
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total time = 120 - 12 sec
\n" ); document.write( "total time = 108 sec
\n" ); document.write( "r = rate going up
\n" ); document.write( "t = time to go up
\n" ); document.write( "\"r%2At+%2B+%28r%2B1%29%2A%28108-t%29+=+480\"
\n" ); document.write( "\"r%2At+=+240\"
\n" ); document.write( "\"r+=+240%2Ft\"
\n" ); document.write( "\"r%2At+%2B+%28r%2B1%29%2A%28108-t%29+=+480\"
\n" ); document.write( "\"240+%2B+%28r%2B1%29%2A%28108-t%29+=+480\"
\n" ); document.write( "\"108r+%2B+108+-rt+-+t+=+240\"
\n" ); document.write( "\"108r+-+240%2Fr+=+372\"
\n" ); document.write( "\"108r%5E2+-+372r+-+240+=+0\"
\n" ); document.write( "\"r+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "\"r+=+%28-%28-372%29+%2B-+sqrt%28+%28-372%29%5E2-4%2A108%2A%28-240%29+%29%29%2F%282%2A108%29+\"
\n" ); document.write( "\"r+=+%28372+%2B-+sqrt%28138384+%2B+103680+%29%29%2F216+\"
\n" ); document.write( "\"r+=+%28372+%2B-+sqrt%28242064+%29%29%2F216+\"
\n" ); document.write( "\"r+=+%28372+%2B+492%29+%2F+216\"
\n" ); document.write( "\"r+=+864%2F216\"
\n" ); document.write( "\"r+=+4\" m/sec answer
\n" ); document.write( "check answer
\n" ); document.write( "\"r%2At+=+240\"
\n" ); document.write( "\"t+=+240%2F4\"
\n" ); document.write( "\"t+=+60\" sec
\n" ); document.write( "\"r%2At+%2B+%28r%2B1%29%2A%28108-t%29+=+480\"
\n" ); document.write( "\"4%2A60+%2B+%284%2B1%29%2A%28108-60%29+=+480\"
\n" ); document.write( "\"240+%2B+5%2A48+=+480\"
\n" ); document.write( "\"240+%2B+240+=+480\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );