document.write( "Question 857269: Use the intermediate value theorem to find the real zero of the given polynomial correct to two decimal places. f(x)=x^3+5x-5 \n" ); document.write( "

Algebra.Com's Answer #516529 by Fombitz(32388) $\"\"$ $\"About$

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$\"f%280%29=-5\"$
\n" ); document.write( " $\"f%281%29=1%2B5-5=1\"$
\n" ); document.write( "So somewhere between $\"x=0\"$ and $\"x=1\"$ , the function crosses the x-axis (has a zero).
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\n" ); document.write( " $\"graph%28300%2C300%2C-2%2C5%2C-2%2C5%2Cx%5E3%2B5x-5%29\"$
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\n" ); document.write( " $\"f%280.8%29=-0.488\"$
\n" ); document.write( " $\"f%280.9%29=0.229\"$
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\n" ); document.write( " $\"f%280.85%29=-0.136\"$
\n" ); document.write( " $\"f%280.87%29=0.0085\"$
\n" ); document.write( "So split the difference.
\n" ); document.write( " $\"x=0.86\"$ \r
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