document.write( "Question 857336: How much pure acid should be mixed with 5 gallons of a 40% acid solution in order to get a 90% acid solution \n" ); document.write( "
Algebra.Com's Answer #516528 by josmiceli(19441)\"\" \"About 
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Let \"+x+\" = gallons of pure acid to be added
\n" ); document.write( "\"+.4%2A5+=+2+\" = gallons of pure acid in 40% solution
\n" ); document.write( "-----------------
\n" ); document.write( "\"+%28+x+%2B+2+%29+%2F+%28+x+%2B+5+%29+=+.9+\"
\n" ); document.write( "\"+x+%2B+2+=+.9%2A%28+x+%2B+5+%29+\"
\n" ); document.write( "\"+x+%2B+2+=+.9x+%2B+4.5+\"
\n" ); document.write( "\"+.1x+=+2.5+\"
\n" ); document.write( "\"+x+=+25+\"
\n" ); document.write( "25 gallons of pure acid must be added
\n" ); document.write( "check:
\n" ); document.write( "\"+%28+x+%2B+2+%29+%2F+%28+x+%2B+5+%29+=+.9+\"
\n" ); document.write( "\"+%28+25+%2B+2+%29+%2F+%28+25+%2B+5+%29+=+.9+\"
\n" ); document.write( "\"+27+%2F+30+=+.9+\"
\n" ); document.write( "\"+9%2F10+=+.9+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );