document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=857299>Question 857299</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do i figure out the surface area of half a cylinder Diameter:45 H:12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #516514 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=516514\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> surface area of cylinder(SA) = 2*pi*r^2 + 2*pi*r*h<BR>\n" );
document.write( "therefore half the SA of a cylinder is <BR>\n" );
document.write( "SA = 1/2(2*pi*r^2 + 2*pi*r*h)<BR>\n" );
document.write( "SA = 1/2(2*pi*(22.5)^2) + (2*pi*(22.5)*12)<BR>\n" );
document.write( "SA = 1/2(3180.86 + 1696.46) = 2438.66<BR>\n" );
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