document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=857289>Question 857289</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the first and second term of an AP is 4,if the tenth term is 19 find the sum of the fifth and sixth terms </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #516476 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=516476\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> an = a + (n - 1)d<BR>\n" );
document.write( "4= 2a + d,<BR>\n" );
document.write( "19= a + 18d<BR>\n" );
document.write( "a = 53/35,   d = 34/35<BR>\n" );
document.write( "check<BR>\n" );
document.write( "53/35+53/35+34/35<BR>\n" );
document.write( "140/35=4<BR>\n" );
document.write( "53/35+612/35=665/35<BR>\n" );
document.write( "s = 53/35 + (4)34/35+ 53/35 + (5)34/35<BR>\n" );
document.write( "s=412/35 =11 27/35<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );