document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=857279>Question 857279</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectanlge has an area of 50cm2, if its length is twice its width, find the perimeter<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #516458 by </B><A HREF=/tutors/aboutme.mpl?userid=Menjax><B>Menjax(62)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Menjax><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=516458\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> call the length x<BR>\n" );
document.write( "call the width y\r<BR>\n" );
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document.write( "x*y = 50cm2 equation 1\r<BR>\n" );
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document.write( "x/2 = y equation 2\r<BR>\n" );
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document.write( "sub equation 2 into equation 1<BR>\n" );
document.write( "x(x/2) = 50<BR>\n" );
document.write( "x2/2-50=0<BR>\n" );
document.write( "factorise (dots/dops)<BR>\n" );
document.write( "(x/sqrt(2) - 5sqrt(2))(x/sqrt(2) + 5sqrt(2))=0<BR>\n" );
document.write( "null factor law:<BR>\n" );
document.write( "x = 5sqrt(2)*sqrt(2) or -5sqrt(2)*sqrt(2)<BR>\n" );
document.write( "x = 10 or -10<BR>\n" );
document.write( "but length cant be negative so it cant be -10<BR>\n" );
document.write( "so x = 10cm and y=5cm\r<BR>\n" );
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