document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=857160>Question 857160</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x+5+3x-10=180       how to find missing measures and solve for x <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #516395 by </B><A HREF=/tutors/aboutme.mpl?userid=rvfer><B>rvfer(117)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rvfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=516395\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x+3x-5=180<BR>\n" );
document.write( "5x=180+5<BR>\n" );
document.write( "x=185/5<BR>\n" );
document.write( "x=37<BR>\n" );
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document.write( "check<BR>\n" );
document.write( "2*37+5+3*37-10=180<BR>\n" );
document.write( "74+5+111-10=180<BR>\n" );
document.write( "180=180 </SPAN>\n" );
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