document.write( "Question 857153: the population standard deviation fro a gas mileage for a certain model of car is known to be 1.8 miles per gallon. how many cars would you have to test(what sample would you need)to get a margin of error of 0.5 mile per gallon (or less) for the population mean at a 90%confidence level? \n" ); document.write( "
Algebra.Com's Answer #516387 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "90% z =1.645
\n" ); document.write( "92% z = 1.751
\n" ); document.write( "95% z = 1.96
\n" ); document.write( "98% z = 2.326
\n" ); document.write( "99% z = 2.576
\n" ); document.write( "ME = .5 =\"+1.645%281.8%2Fsqrt%28n%29%29%29\"
\n" ); document.write( " sqrt(n) = 1.645*1.8/.5 = 5.922
\n" ); document.write( " n= 35.07 0r approximately 36
\n" ); document.write( " \n" ); document.write( "
\n" );