Algebra.Com's Answer #51638 by jim_thompson5910(35256)![\"\"](\"/images/stars/stars-13.gif\")  
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When you are solving for x, you have the following form
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document.write( " Where p and q are factors of f(x). For instance p could equal (x-5) and q could equal (x+6). To solve for x, you set p and q equal to zero and isolate x. But this time you know what x is, you just need to find the factor that makes the polynomial. So if you have x=3 and x=-1, lets take x=3 first. What number adds to 3 to get 0? Well it would be -3. So in other words 3-3=0. If we replace the 1st 3 with x we get
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document.write( " Theres one factor (if we plug in 3 for x, we get 0)
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document.write( " There's the other factor, just do the same as before.
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document.write( "So now you multiply them together
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document.write( " FOIL
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document.write( " Thats the polynomial with roots of x=-1 and x=3
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document.write( "Check:
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document.write( " Plug in x=-1
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document.write( " Works
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document.write( "Plug in x=3
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document.write( "Works
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document.write( "It turns out in a product of factors
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document.write( " The roots are x=-a and x=-b. Just a note for quick reference. So if you have any two roots, you can go backwards to get the equation.\r
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