document.write( "Question 72240This question is from textbook Algebra 1
\n" ); document.write( ": Find the vertex for y=3(x-5)squared+2 \n" ); document.write( "
Algebra.Com's Answer #51634 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
In the general equation of a quadratic
\n" ); document.write( "\"y=%28x-h%29%5E2%2Bk\" Represents a quadratic in \"vertex form\", in other words the vertex is (h,k). The constant h is the horizontal shift of the vertex and k is the vertical shift of the vertex. For instance if you have \"y=x%5E2\" it looks like this
\n" ); document.write( "\"graph%28+300%2C+200%2C+-5%2C+5%2C+-5%2C+5%2C+x%5E2%29\"The graph of \"y=x%5E2\"
\n" ); document.write( "Where the vertex is at (0,0). If you want to shift the graph up or down, you simply add or subtract the appropriate units. For instance, to shift 3 units up, just add 3.
\n" ); document.write( "\"graph%28+300%2C+200%2C+-5%2C+5%2C+-5%2C+5%2C+x%5E2%2B3%29\"The graph of \"y=x%5E2%2B3\" (note: h=0 k=3)
\n" ); document.write( "For this problem, the shifted units are given to you and all you have to do is find the vertex. If the vertex started at (0,0) and we shifted 2 units up and 5 units to the right then the vertex would be (5,2).
\n" ); document.write( "\"graph%28+300%2C+200%2C+0%2C+10%2C+-5%2C+5%2C+3%2A%28x-5%29%5E2%2B2%29\"The vertex is the lowest point on the graph
\n" ); document.write( " \n" ); document.write( "
\n" );