document.write( "Question 857016: The Customer Service Center in a large New York department store has determined that the amount of time spent with a customer about a complaint is normally distributed, with a mean of 9.5 minutes and a standard deviation of 2.4 minutes. What is the probability that for a randomly chosen customer with a complaint, the amount of time spent resolving the complaint will be as follows. (Round your answers to four decimal places.)
\n" ); document.write( " (a) less than 10 minutes
\n" ); document.write( ".2083 . \r
\n" ); document.write( "\n" ); document.write( "(b) longer than 5 minutes\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " (c) between 8 and 15 minutes
\n" ); document.write( "

Algebra.Com's Answer #516324 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "mean of 9.5 minutes and a standard deviation of 2.4 minutes.
\n" ); document.write( "a) P(x< 10min) Yes, z = .2083 P = NORMSDIST(.2083) = .5825
\n" ); document.write( "b) P(x> 5min) = 1 - NORMSDIST(-4.5/2.4)
\n" ); document.write( "c) P(8 ≤ x ≤ 15) = NORMSDIST(6.5/2.4) - NORMSDIST(-1.5/2.4)\r
\n" ); document.write( "\n" ); document.write( "TI function normalcdf(smaller, larger, µ, σ) can also be used \n" ); document.write( "
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