document.write( "Question 72232: the sum of the two-digit number is 11. When the number is reversed, the number is 63 less than the original number. Find the original number and show work. \n" ); document.write( "
Algebra.Com's Answer #51630 by stanbon(75887)\"\" \"About 
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the sum of the two-digit number is 11. When the number is reversed, the number is 63 less than the original number. Find the original number and show work.
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\n" ); document.write( "Let the two digit number be tu: t is the ten's digit; u is the unit's digit
\n" ); document.write( "The value of this number is 10t+u just like 23 is worth 10*2+3
\n" ); document.write( "The value of its reverse is 10u+t
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\n" ); document.write( "EQUATION:
\n" ); document.write( "t+u=11
\n" ); document.write( "10u+t+63=10t+u
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\n" ); document.write( "Rewrite as:
\n" ); document.write( " t+u=11
\n" ); document.write( " 9t-9u=63
\n" ); document.write( "---------------
\n" ); document.write( "Rewrite Again:
\n" ); document.write( "t+u=11
\n" ); document.write( "t-u=7
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\n" ); document.write( "Add the two equations to get:
\n" ); document.write( "2t=18
\n" ); document.write( "t=9
\n" ); document.write( "-------
\n" ); document.write( "Solve for u:
\n" ); document.write( "9+u=11
\n" ); document.write( "u=2
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\n" ); document.write( "The original number is 92
\n" ); document.write( "The number reversed is 29
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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