document.write( "Question 842311: What are multiples of 1/5 and how do you write the multiples as a sum \n" ); document.write( "
Algebra.Com's Answer #516252 by richwmiller(17219)\"\" \"About 
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Curiously even though we are talking about multiples of 1/5 it will be an arithmetic sequence not geometric.
\n" ); document.write( "1/5, 2/5, 3/5,4/5\r
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\n" ); document.write( "\n" ); document.write( "First term is 1/5 and the difference is 1/5
\n" ); document.write( "S = ½(2a + (n-1)d)n
\n" ); document.write( "positive S = ½(2/5 + (n-1)/5)n
\n" ); document.write( "negative S = ½(-2/5 -(n-1)/5)n
\n" ); document.write( "If we also include negative multiples of 1/5
\n" ); document.write( "First term is -1/5 and the difference is -1/5
\n" ); document.write( "then the sum will be zero because the pluses and minuses add up to zero.\r
\n" ); document.write( "\n" ); document.write( "S = ½(2/5 + (n-1)/5)n+ ½(-2/5 -(n-1)/5)n=0
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