document.write( "Question 856935: Hi, I've been having trouble with this problem for days. \r
\n" ); document.write( "\n" ); document.write( "Perform the indicated operations and express the answer in simplest form:
\n" ); document.write( "n/n-2 + n+3/n+7 + 15n+69/n^2+5n-14\r
\n" ); document.write( "\n" ); document.write( "I got the factors as (n+7)(n-2) and then multiplied each so that the denominators would be the same. I then got: (n)(n+7)+(n+3)(n-2)+15n+69.\r
\n" ); document.write( "\n" ); document.write( "=n^2+7n+n^2-2n+3n-6+15n+69
\n" ); document.write( "=2n^2+23n+63/(n+7)(n+2)\r
\n" ); document.write( "\n" ); document.write( "Thank you for your help!!
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Algebra.Com's Answer #516245 by richwmiller(17219) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"n%2F%28n-2%29+%2B+%28n%2B3%29%2F%28n%2B7%29+%2B+%2815n%2B69%29%2F%28n%5E2%2B5n-14%29+\"$ \r
\n" ); document.write( "\n" ); document.write( "Since (n^2+5n-14)=(n+7)(n-2)\r
\n" ); document.write( "\n" ); document.write( "But you changed the sign 2n^2+23n+63/(n+7)(n+2)
\n" ); document.write( "It should be (n-2) not (n+2)
\n" ); document.write( "2n^2+23n+63/(n+7)(n-2)
\n" ); document.write( "2n^2+23n+63=(2n+9) (n+7)
\n" ); document.write( "(n-2) /(n-2) cancels out and we have
\n" ); document.write( "It all reduces to
\n" ); document.write( "(2n+9)/(n-2) when n is not -7 \n" ); document.write( "

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