document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=856939>Question 856939</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The speed of a boat in still water is 10 mph.  If the boat travels 108 miles upstream in the same time it takes to travel 132 miles downstream, find the speed of the current. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #516244 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=516244\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The speed of a boat in still water is 10 mph. If the boat travels 108 miles upstream in the same time it takes to travel 132 miles downstream, find the speed of the current.<BR>\n" );
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document.write( "Upstream DATA:<BR>\n" );
document.write( "dist = 108 miles ; rate = c-10 mph ; time = d/r = 108/(c-10)<BR>\n" );
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document.write( "Downstream DATA:<BR>\n" );
document.write( "dist = 132 miles ; rate = c+10 mph ; time = 132/(c+10)<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "108/(c-10) = 132/(c+10)<BR>\n" );
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document.write( "108c + 1080 = 132c - 1320<BR>\n" );
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document.write( "24c = 2400<BR>\n" );
document.write( "c = 100 mph (rate of the current-----unbelievable)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );