document.write( "Question 856652: The equation of hyperbola H is \r
\n" ); document.write( "\n" ); document.write( "(x+4)^2/64 - (y+3)^3/16 = 1\r
\n" ); document.write( "\n" ); document.write( "What are the asymptotes?
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Algebra.Com's Answer #516168 by lwsshak3(11628)\"\" \"About 
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The equation of hyperbola H is
\n" ); document.write( "(x+4)^2/64 - (y+3)^3/16 = 1
\n" ); document.write( "What are the asymptotes?
\n" ); document.write( "***
\n" ); document.write( "Given hyperbola has a horizontal transverse axis.
\n" ); document.write( "Its standard form of equation: \"%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1\"
\n" ); document.write( "For given hyperbola:
\n" ); document.write( "center: (-4,-3)
\n" ); document.write( "a^2=64
\n" ); document.write( "a=8
\n" ); document.write( "b^2=16
\n" ); document.write( "b=4:
\n" ); document.write( "asymptotes are equations of straight lines of standard form: y=mx+b, m=slope, b=y-intercept
\n" ); document.write( "slopes=±b/a=±4/8=±1/2
\n" ); document.write( "asymptotes go thru center(-4,-3)
\n" ); document.write( "..
\n" ); document.write( "Equation of asymptote with slope<0
\n" ); document.write( "y=-x/2+b
\n" ); document.write( "solve for b using coordinates of center
\n" ); document.write( "-3=-(-4)/2+b
\n" ); document.write( "b=-5
\n" ); document.write( "equation:y=-x/2-5
\n" ); document.write( "..
\n" ); document.write( "Equation of asymptote with slope>0
\n" ); document.write( "y=x/2+b
\n" ); document.write( "solve for b using coordinates of center
\n" ); document.write( "-3=-4)/2+b
\n" ); document.write( "b=-1
\n" ); document.write( "equation:y=x/2-1
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