document.write( "Question 856652: The equation of hyperbola H is \r
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document.write( "(x+4)^2/64 - (y+3)^3/16 = 1\r
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document.write( "What are the asymptotes? \n" );
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Algebra.Com's Answer #516168 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! The equation of hyperbola H is \n" ); document.write( "(x+4)^2/64 - (y+3)^3/16 = 1 \n" ); document.write( "What are the asymptotes? \n" ); document.write( "*** \n" ); document.write( "Given hyperbola has a horizontal transverse axis. \n" ); document.write( "Its standard form of equation: \n" ); document.write( "For given hyperbola: \n" ); document.write( "center: (-4,-3) \n" ); document.write( "a^2=64 \n" ); document.write( "a=8 \n" ); document.write( "b^2=16 \n" ); document.write( "b=4: \n" ); document.write( "asymptotes are equations of straight lines of standard form: y=mx+b, m=slope, b=y-intercept \n" ); document.write( "slopes=±b/a=±4/8=±1/2 \n" ); document.write( "asymptotes go thru center(-4,-3) \n" ); document.write( ".. \n" ); document.write( "Equation of asymptote with slope<0 \n" ); document.write( "y=-x/2+b \n" ); document.write( "solve for b using coordinates of center \n" ); document.write( "-3=-(-4)/2+b \n" ); document.write( "b=-5 \n" ); document.write( "equation:y=-x/2-5 \n" ); document.write( ".. \n" ); document.write( "Equation of asymptote with slope>0 \n" ); document.write( "y=x/2+b \n" ); document.write( "solve for b using coordinates of center \n" ); document.write( "-3=-4)/2+b \n" ); document.write( "b=-1 \n" ); document.write( "equation:y=x/2-1 \n" ); document.write( " |