document.write( "Question 856859: Solve the equation for x: x^4-32x^2-256=0\r
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Algebra.Com's Answer #516163 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Make the substitution:
\n" ); document.write( "\"+z+=+x%5E2+\"
\n" ); document.write( "and
\n" ); document.write( "\"+z%5E2+=+x%5E4+\"
\n" ); document.write( "--------------------------
\n" ); document.write( "\"+z%5E2+-+32z+-+256+=+0+\"
\n" ); document.write( "\"+z+=+%28+-b+%2B-+sqrt%28+b%5E2+-+4%2Aa%2Ac+%29%29+%2F+%282%2Aa%29+\"
\n" ); document.write( "\"+a+=+1+\"
\n" ); document.write( "\"+b+=+-32+\"
\n" ); document.write( "\"+c+=+-256+\"
\n" ); document.write( "\"+z+=+%28+-%28-32%29+%2B-+sqrt%28+%28-32%29%5E2+-+4%2A1%2A%28-256%29+%29%29+%2F+%282%2A1%29+\"
\n" ); document.write( "\"+z+=+%28+32+%2B-+sqrt%28+1024+%2B+1024+%29%29+%2F+2+\"
\n" ); document.write( "\"+z+=+%28+32+%2B-+sqrt%28+2048+%29%29+%2F+2+\"
\n" ); document.write( "\"+z+=+%28+32+%2B-+32%2Asqrt%282%29%29+%2F+2+\"
\n" ); document.write( "\"+z+=+16%2A%28+1+%2B+sqrt%282%29+%29+\"
\n" ); document.write( "\"+z+=+16%2A%28+1+-+sqrt%282%29+%29+\"
\n" ); document.write( "-------------------------------
\n" ); document.write( "\"+z+=+x%5E2+\"
\n" ); document.write( "\"+x+=+sqrt%28z%29+\"
\n" ); document.write( "\"+x+=+-sqrt%28z%29+\"
\n" ); document.write( "--------------------------
\n" ); document.write( "\"+x+=+4%2Asqrt%28+1+%2B+sqrt%282%29+%29+\"
\n" ); document.write( "\"+x+=+-4%2Asqrt%28+1+%2B+sqrt%282%29+%29+\"
\n" ); document.write( "\"+x+=+4%2Asqrt%28+1+-+sqrt%282%29+%29+\" ( imaginary root )
\n" ); document.write( "\"+x+=+-4%2Asqrt%28+1+-+sqrt%282%29+%29+\" ( imaginary root )
\n" ); document.write( "You can plug these back in to check\r
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