document.write( "Question 856754: How do I graph this function over a 2-period interval? Can you explain step by step please?\r
\n" ); document.write( "\n" ); document.write( "The function is y = 3 + 1/2 tanx \n" ); document.write( "
Algebra.Com's Answer #516151 by stanbon(75887)\"\" \"About 
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How do I graph this function over a 2-period interval? Can you explain step by step please?
\n" ); document.write( "The function is y = 3 + 1/2 tanx
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\n" ); document.write( "\"graph%28400%2C400%2C-6%2C6%2C-10%2C10%2C3+%2B+%281%2F2%29tan%28x%29%29\"
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\n" ); document.write( "Graphing:
\n" ); document.write( "If x = 0, y = 3
\n" ); document.write( "If x = pi/6, y = 3+sqrt(3)/3 = 3.577
\n" ); document.write( "If x = pi/3, y = 3+sqrt(3) = 3 + 1.73 = 4.73
\n" ); document.write( "If x = -pi/6, y = 3.577
\n" ); document.write( "If x = -pi/3, y = -4.73
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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