document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=856786>Question 856786</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many liters of 20% antifreeze  solution and a 40% antifreeze solution must be mixed  to make 10 liters of a 28% antifreeze solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #516140 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=516140\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how many liters of 20% antifreeze solution and a 40% antifreeze solution must be mixed to make 10 liters of a 28% antifreeze solution?<BR>\n" );
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document.write( "let x=amt of 20% antifreeze solution to mix<BR>\n" );
document.write( "10-x=amt of 40% antifreeze solution to mix<BR>\n" );
document.write( "..<BR>\n" );
document.write( "20%x+40%(10-x)=28%*10<BR>\n" );
document.write( ".20x+4-.40x=2.8<BR>\n" );
document.write( ".20x=1.2<BR>\n" );
document.write( "x=6<BR>\n" );
document.write( "10-x=4<BR>\n" );
document.write( "amt of 20% antifreeze solution to mix=6 liters<BR>\n" );
document.write( "amt of 40% antifreeze solution to mix=4 liters </SPAN>\n" );
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