document.write( "Question 856798: the expression sin2A - 2sinA is equivalent to:\r
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Algebra.Com's Answer #516138 by harpazo(655)\"\" \"About 
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\n" ); document.write( "Note: sin2A = 2sinAcosA\r
\n" ); document.write( "\n" ); document.write( "Then 2sinAcosA - 2sinA.\r
\n" ); document.write( "\n" ); document.write( "Factor out 2sinA.\r
\n" ); document.write( "\n" ); document.write( "Answer: 2sinA(cosA - 1)
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