document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=856789>Question 856789</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a boat averages 20 mph in still water. It takes the boat the same amount of time to travel 3 miles with the currents as it does to travel 2 miles against the current. What is the currents rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #516136 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=516136\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a boat averages 20 mph in still water. It takes the boat the same amount of time to travel 3 miles with the currents as it does to travel 2 miles against the current. What is the currents rate?<BR>\n" );
document.write( "***<BR>\n" );
document.write( "let c=rate of current<BR>\n" );
document.write( "20+c=rate of boat with current<BR>\n" );
document.write( "20-c=rate of boat against current<BR>\n" );
document.write( "travel time=distance/rate (equal in both directions)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "3/(20+c)=2/(20-c)<BR>\n" );
document.write( "60-3c=40+2c<BR>\n" );
document.write( "5c=20<BR>\n" );
document.write( "c=4<BR>\n" );
document.write( "rate of current=4 mph </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );