document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=72212>Question 72212</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0072934662/algebrahomeworkh>Elementary Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Simply the complex fraction if possible\r<BR>\n" );
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document.write( "4+(3/y)/1-(2/y) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #51611 by </B><A HREF=/tutors/aboutme.mpl?userid=pradhyumna.kumar@gmail.com><B>pradhyumna.kumar@gmail.com(62)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=pradhyumna.kumar@gmail.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=51611\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Simply the complex fraction if possible\r<BR>\n" );
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document.write( "4+(3/y)/1-(2/y) =  after doing the L.C.M ofr y in the numerator and the denominator we get, <BR>\n" );
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document.write( "        4+(3/y)/1-(2/y)   = (4y+3)/(y-2)  </SPAN>\n" );
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