document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=846732>Question 846732</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the first two terms of an exponential sequence is 135 and the sum of the third and the fourth terms is 60. Given that the common ratio is positive, calculate the common ratio and d first term </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #516038 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=516038\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Tn = t * r^(n - 1)\r<BR>\n" );
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document.write( "T2 = t * r<BR>\n" );
document.write( "T2+T1=135<BR>\n" );
document.write( "t*r+t=135\r<BR>\n" );
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document.write( "T3 = t * r^2<BR>\n" );
document.write( "T4 = t * r^3<BR>\n" );
document.write( "T3+T4=60<BR>\n" );
document.write( "t*r^2+t*r^3=60,<BR>\n" );
document.write( "(r^3+r^2)t = 60<BR>\n" );
document.write( "t*r+t=135<BR>\n" );
document.write( "(r+1)*t = 135\r<BR>\n" );
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document.write( "(r^3+r^2)t = 60<BR>\n" );
document.write( "(r+1)*t = 135<BR>\n" );
document.write( "r = 2/3,   t1 = 81 </SPAN>\n" );
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