document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=846691>Question 846691</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An exponential sequence is such that the third term minus the first term is 48. The fourth term minus the second term is 144. Find the common ratio, the first term, the sixth term </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #516035 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=516035\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Tn = t * r^(n - 1)\r<BR>\n" );
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document.write( "T3 = t * r^2<BR>\n" );
document.write( "T1 = t<BR>\n" );
document.write( "t3-t1=48<BR>\n" );
document.write( "(t * r^2)-t=48<BR>\n" );
document.write( "T4 = t * r^(3)<BR>\n" );
document.write( "T2 = t * r^(1)<BR>\n" );
document.write( "t4-t2=144<BR>\n" );
document.write( "t * r^(3)- t * r^(1)=144<BR>\n" );
document.write( "r = 3,   t1 = 6<BR>\n" );
document.write( "T6 = 6 * 3^(5)<BR>\n" );
document.write( "T6 = 1458<BR>\n" );
document.write( " </SPAN>\n" );
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