document.write( "Question 844488: Find five consecutive terms of an a.p whose sum is 45 and sum of cubes of 2nd and 4th term is 1944 \n" ); document.write( "
Algebra.Com's Answer #516014 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! S = ½(a + an)n \n" ); document.write( "45 = ½(2a + (5-1)d)5 \n" ); document.write( "an = a1 + (n - 1)d \n" ); document.write( "9=a + 2d, \n" ); document.write( "b^3+c^3=1944, \n" ); document.write( "a2=b = a + d, \n" ); document.write( "a4=c = a + 3d, \n" ); document.write( "two answers \n" ); document.write( "a1 = 3, a2= b = 6, a4=c = 12, d = 3\r \n" ); document.write( "\n" ); document.write( "3,6,9,12,15 \n" ); document.write( "S = ½(a + an)n \n" ); document.write( "s=1/2(3+15)*5 \n" ); document.write( "s=1/2(18)*5 \n" ); document.write( "s=45 \n" ); document.write( "6^3+12^3 \n" ); document.write( "216+1728=1944 \n" ); document.write( "and\r \n" ); document.write( "\n" ); document.write( "a1 = 15, a2= b = 12, a4= c = 6, d = -3 \n" ); document.write( "15,12,9,6,3 \n" ); document.write( "same numbers in reverse \n" ); document.write( "a2 and a4 are again 12 and 6 \n" ); document.write( "same results\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |