document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=856341>Question 856341</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Four cards are drawn from a pack of 52 cards.  What is the probability that a card from each of the four suits is obtained?\r<BR>\n" );
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document.write( "I have the following:<BR>\n" );
document.write( "13/52 (probability of 1st card of 1 suit) x 12/51 (probability of 2nd card from same suit) x 11/50 (prob. 3rd card from same suit) x 10/49 (prob. of 4th card from same suit) = 11/4165 [No. of desired outcomes]<BR>\n" );
document.write( "I divided this by 52C4 [No. of possible outcomes] to get answer: 9.755 x 10 to power of -9\r<BR>\n" );
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document.write( "Can you advise on my method please?<BR>\n" );
document.write( "Thanking you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #515923 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=515923\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The probability of the first card is 1 (any one will do).<BR>\n" );
document.write( "Card 2 probability is 3*13/51 = 13/17.<BR>\n" );
document.write( "Card 3 probability is 2*13/50 = 13/25.<BR>\n" );
document.write( "Card 4 probability is 13/49 = 13/49<BR>\n" );
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document.write( "13^3/(17*25*49)<BR>\n" );
document.write( "=2197/20825<BR>\n" );
document.write( "=~ 0.1055<BR>\n" );
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document.write( "Ed </SPAN>\n" );
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