document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=856397>Question 856397</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the base of a triangle is two m less thsn twice its height find the length of the base and the height given that the area of thr triangles  is 56 sq m </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #515911 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=515911\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> height = x<BR>\n" );
document.write( "base = 2x-2\r<BR>\n" );
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document.write( "Area of triangle = 1/2 * base * height\r<BR>\n" );
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document.write( "56 = 1/2 * x * 2(x-1)\r<BR>\n" );
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document.write( "56=x(x-1)\r<BR>\n" );
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document.write( "56=x^2-x\r<BR>\n" );
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document.write( "x^2-x-56=0\r<BR>\n" );
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document.write( "x^2-8x+7x-56=0\r<BR>\n" );
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document.write( "x(x-8)+7(x-8)=0\r<BR>\n" );
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document.write( "(x-8)(x+7)=0\r<BR>\n" );
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document.write( "take positive value.<BR>\n" );
document.write( "x= 8\r<BR>\n" );
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document.write( "height = 8 m<BR>\n" );
document.write( "base = 2x-2 = 14 m </SPAN>\n" );
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