document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=856377>Question 856377</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am currently stuck on this problem the equation is 6v^2+19v-36=0 i understand that i need to factor but I just can't get to the answer, i have tried (3v+3)(2v+12) but i can't get it.. Please help(: </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #515878 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=515878\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the equation is 6v^2+19v-36=0 i understand that i need to factor but I just can't get to the answer, i have tried (3v+3)(2v+12)<BR>\n" );
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document.write( "The signs of the 3 & 12 can't both be positive since the product is -36.<BR>\n" );
document.write( "Try something else, some other combination.<BR>\n" );
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