document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=856287>Question 856287</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A and B are positive acute angles. If sinA=4/5 and cosB=8/17, find the value of tan(A-B)<BR>\n" );
document.write( "My work:<BR>\n" );
document.write( "Tan(A-B)= tan(4/5)-tan(8/17)  /   1+tan(4/5)tan(8/17)<BR>\n" );
document.write( "= .0057493832 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #515843 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=515843\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A and B are positive acute angles. If sinA=4/5 and cosB=8/17, find the value of tan(A-B)<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "If sin(A) = 4/5, cos(A) = sqrt[5^2-4^2]/5 = 3/5<BR>\n" );
document.write( "Then tan(A) = sin/cos = 4/3<BR>\n" );
document.write( "======<BR>\n" );
document.write( "If cos(B) = 8/17, sin(B) = sqrt(17^2-8^2]/17 = 15/17<BR>\n" );
document.write( "Then tan(B) = sin/cos = 17/8<BR>\n" );
document.write( "===================================<BR>\n" );
document.write( "Your Problem:<BR>\n" );
document.write( "tan (A-B) = [(4/3)+(15/17)]/[1-(4/3)(15/17)]  = -12.56<BR>\n" );
document.write( "============================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );