document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=856275>Question 856275</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the equation of the line that is perpendicular to the line x-3y-7=0 and passes through the point (9,-3)in standard form and general form<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #515841 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=515841\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the equation of the line that is perpendicular to the line x-3y-7=0 and passes through the point (9,-3)in standard form and general form<BR>\n" );
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document.write( "Given Line DATA:<BR>\n" );
document.write( "x - 3y - 7 = 0<BR>\n" );
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document.write( "3y = x-7<BR>\n" );
document.write( "y = (1/3)x -(7/3)<BR>\n" );
document.write( "slope = 1/3<BR>\n" );
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document.write( "New Line DATA:<BR>\n" );
document.write( "Form:: y = mx + b<BR>\n" );
document.write( "slope = -3<BR>\n" );
document.write( "passes thru 9,-3<BR>\n" );
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document.write( "-3 = -3*9 + b<BR>\n" );
document.write( "b = 24<BR>\n" );
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document.write( "New Equation:<BR>\n" );
document.write( "y = -3x + 24<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "==================== </SPAN>\n" );
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