document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=856081>Question 856081</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Emily rows six miles downstream in 1 hour and her friend Ashley, rowing 1 mile per hour faster,completes the return trip in 2 hours.\r<BR>\n" );
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document.write( "a) Find the speed of the current and each girl's rowing speed. \r<BR>\n" );
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document.write( "b)  If Emily and Ashley were rowing separately, who would complete their trip first and by how long? (Round to hundredths if necessary) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #515837 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=515837\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Emily rows six miles downstream in 1 hour and her friend Ashley, rowing 1 mile per hour faster, completes the return trip in 2 hours.<BR>\n" );
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document.write( "a) Find the speed of the current and each girl's rowing speed.<BR>\n" );
document.write( "Let s = E's rowing speed<BR>\n" );
document.write( "then<BR>\n" );
document.write( "(s+1) = A's rowing speed<BR>\n" );
document.write( "let c = speed of the current<BR>\n" );
document.write( "Write an distance equation for each way. (Dist = speed * time<BR>\n" );
document.write( "1(s + c) = 6<BR>\n" );
document.write( "and<BR>\n" );
document.write( "2(s+1-c) = 6<BR>\n" );
document.write( "simplify the equation, divide by 2<BR>\n" );
document.write( "s + 1 - c = 3<BR>\n" );
document.write( "s - c = 3 - 1<BR>\n" );
document.write( "s - c = 2<BR>\n" );
document.write( "Use elimination on the two equation<BR>\n" );
document.write( "s + c = 6<BR>\n" );
document.write( "s - c = 2<BR>\n" );
document.write( "------------adding eliminates c, find s<BR>\n" );
document.write( "2s = 8<BR>\n" );
document.write( "s = 4 mph is E's rowing speed, and 5 mph is A's rowing speed<BR>\n" );
document.write( "find the current<BR>\n" );
document.write( "4 + c = 6<BR>\n" );
document.write( "c = 6 - 4<BR>\n" );
document.write( "c = 2 mph is the current<BR>\n" );
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document.write( "b) If Emily and Ashley were rowing separately, who would complete their trip first and by how long? (Round to hundredths if necessary)<BR>\n" );
document.write( "A rows 1 mph faster so she would complete the trip first<BR>\n" );
document.write( "E's round trip time (6 mph down, 2 mph back)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6%2F6 ALIGN=MIDDLE  ALT=\"6%2F6\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6%2F2 ALIGN=MIDDLE  ALT=\"6%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 4 hrs<BR>\n" );
document.write( "A's round trip time (7 mph down, 3 mph back)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6%2F7 ALIGN=MIDDLE  ALT=\"6%2F7\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6%2F3 ALIGN=MIDDLE  ALT=\"6%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 2.857 hrs<BR>\n" );
document.write( "Difference:<BR>\n" );
document.write( "4 - 2.857 = 1.14 hrs less<BR>\n" );
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