document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=72172>Question 72172</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Moly is 3 years younger than Havier. In 3 year, havier will be as twice as molly age. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #51575 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=51575\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> M=H-3<BR>\n" );
document.write( "H+3=2M SUBSTITUTING (H-3)FOR M IN THE SECOND EQUATION WE GET:<BR>\n" );
document.write( "H+3=2(H-3)<BR>\n" );
document.write( "H+3=2H-6<BR>\n" );
document.write( "H-2H-6-3<BR>\n" );
document.write( "-H=-9<BR>\n" );
document.write( "H=9 HAVIER IS NOW 9 YEARS OLD & MOLLY IS 9-3=6 YEARS OLD.<BR>\n" );
document.write( "SO IN THREE YEARS HAVIER WILL BE 9+3=12 OR HAVIER WILL BE TWICE AS OLD AS MOLLY IS.<BR>\n" );
document.write( "6*2=12<BR>\n" );
document.write( "12=12\r<BR>\n" );
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document.write( " </SPAN>\n" );
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