document.write( "Question 856103: This is a question on my study guide for my test and I don't know how to solve this. If I can't figure this out, then I might fail my test. Please help me! I would greatly appreciate it.\r
\n" ); document.write( "\n" ); document.write( "The population of a local species of dragonfly can be found using an infinite geometric series where a1 = 36 and the common ratio is 1/2. Write the sum in sigma notation and calculate the sum that will be the upper limit of this population.
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Algebra.Com's Answer #515744 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
the sum of an infinite geometric series is equal to a1 / (1-r).
\n" ); document.write( "r = 1/2
\n" ); document.write( "a1 = 36
\n" ); document.write( "sum is equal to 36 / (1 - 1/2) which is equal to 36/(1/2) which is equal to 72.
\n" ); document.write( "that's your answer.
\n" ); document.write( "the formula for the sum of a geometric series is normally shown as:
\n" ); document.write( "Sn = A1 / (1-r)
\n" ); document.write( "A1 is the first term in the sequence.
\n" ); document.write( "Sn is the sum of all the terms.
\n" ); document.write( "the following link discusses geometric series:
\n" ); document.write( "http://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/col_alg_tut54d_geom.htm
\n" ); document.write( "if you are not familiar with how they work, this is a good review.
\n" ); document.write( "scroll down about 3/4 of the way down the page to get to sum of an infinite geometric series.\r
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