document.write( "Question 72168: My instructor made this question up. But we use the Second Edition, Intermediate Algebra testbook, by Bittinger, ellenbogen, Johnson and chapter 6 - sorry if you have answered a question like this already? I saw some similar but not with the \"skill water\"...
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\n" ); document.write( "A boat travels 10 miles per hour in still water. It travels 20 miles down a river in the same time that it travels 5 miles up the same river. What is the speed of the River? \r
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Algebra.Com's Answer #51573 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
20/(10+X)=5/(10-X) CROSS MULTIPLY
\n" ); document.write( "5(10+X)=20(10-X)
\n" ); document.write( "50+5X=200-20X
\n" ); document.write( "5X+20X=200-50
\n" ); document.write( "25X=150
\n" ); document.write( "X=150/25
\n" ); document.write( "X=6 MPH FOR THE CURRENT
\n" ); document.write( "PROOF
\n" ); document.write( "20/16=5/4
\n" ); document.write( "1.25=1.25
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\n" ); document.write( "NEW PROBLEM: THESE ARE THE VERY EASY ONES
\n" ); document.write( "X*Y/(X+Y)=TOTAL TIME WHERE X & Y ARE THE TIMES IT TAKES EACH ONE INDICVIDUALLY TO DO SOMETHING OR WVWN PIPES TO FILL/EMPTY A POOL.
\n" ); document.write( "IN YOU PROBLEM WE HAVE A 40 MINTE JOB & AN UNKNOWN JOB TIME THAT ENDS UP BEING A 15 MINUTE JOB IF COMBINED. THUS LET X BE THE UNKNOW TIME.
\n" ); document.write( "40X/(40+X)=15 NOW CROSS MULTIPLY
\n" ); document.write( "40X=15(40+X)
\n" ); document.write( "40X=600+15X
\n" ); document.write( "40X-15X=600
\n" ); document.write( "25X=600 X=600/25
\n" ); document.write( "X=24 MINUTES FOR THE OTHER PERSON TO DO THE JOB ALONE.
\n" ); document.write( "PROOF
\n" ); document.write( "40*24/(40+24)=15
\n" ); document.write( "960/64=15
\n" ); document.write( "15=15
\n" ); document.write( "HAPPY MATHING\r
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