document.write( "Question 856038: One integer is 10 less than 3 times another. The sum of their squares is 100. What are the two integers? \n" ); document.write( "
Algebra.Com's Answer #515705 by ramkikk66(644)\"\" \"About 
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document.write( "Let one integer be x. Then the other is 3*x - 10\r\n" );
document.write( "Sum of squares = \"x%5E2+%2B+%283%2Ax+-+10%29%5E2%29+=+x%5E2+%2B+9%2Ax%5E2+-+60%2Ax+%2B+100+=+100\"\r\n" );
document.write( "i.e. \"10%2Ax%5E2+-+60%2Ax+=+0\"\r\n" );
document.write( "Simplifying\r\n" );
document.write( "\"x%2A%28x+-+6%29+=+0\"\r\n" );
document.write( "So, \"x+=+0\" or \"x+=+6\"\r\n" );
document.write( "If x = 0, the other number = 3*0 - 10 = -10\r\n" );
document.write( "If x = 6, the other number = 3*6 - 10 = 8\r\n" );
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document.write( "So the solutions are (0,-10) or (6,8)\r\n" );
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document.write( "Hope this clarifies :)\r\n" );
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