document.write( "Question 856048: Bob is 25 years younger than his father and 27 years older than his son. Together, their ages sum up to 100. What is each of their ages? \n" ); document.write( "

Algebra.Com's Answer #515704 by hamsanash1981@gmail.com(151) $\"\"$ $\"About$

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Let Bob's father age be x then bob's age = x - 25 and his son's age = x-25 - 27
\n" ); document.write( "=> x- 52
\n" ); document.write( "Their ages sum =100
\n" ); document.write( "x+x-25+x-52 = 100
\n" ); document.write( "3x - 77 = 100
\n" ); document.write( "3x = 177
\n" ); document.write( "x = 59\r
\n" ); document.write( "\n" ); document.write( "Therefore bob's father age = 59
\n" ); document.write( "Bob's age = x-25 = 59 - 25 = 34
\n" ); document.write( "Bob's son age = x- 52 = 59 - 52 = 7
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